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x^2+7x=108
We move all terms to the left:
x^2+7x-(108)=0
a = 1; b = 7; c = -108;
Δ = b2-4ac
Δ = 72-4·1·(-108)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{481}}{2*1}=\frac{-7-\sqrt{481}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{481}}{2*1}=\frac{-7+\sqrt{481}}{2} $
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